Converting Decimal Numbers to Binary Numbers and Vice Versa in C++

#include <iostream>
#include <cmath>
using namespace std;
long long DecimalToBinary(int);
int main()
{
    int num, ans;
    cout << "Insert any decimal number to be converted: ";
    cin >> num;
    ans = DecimalToBinary(num);
    cout << num << " is " << ans << " in Binary" << endl ;
    return 0;
}
long long DecimalToBinary(int num)
{
    long long ans = 0;
    int y,x = 1;
    while (num!=0)
    {
        y = num%2;
        num /= 2;
        ans += y*x;
        x *= 10;
    }
    return ans;
}

Insert any decimal number to be converted: 364
 364 is 101101100 in Binary

• This function uses recursion DecimalToBinary ().
• num is divided by 2 and the remainder is stored as y.
• num is assigned a new value by num = num/2.
• ans is also assigned a new value: ans = ans + y*x
• x is assigned a new value: x = x*10
• If the remainder of num when divided by 2 is 0, x will also be equal to 0.
• The answer is printed on screen.

#include <iostream>
#include <cmath>
using namespace std;
int BinaryToDecimal(long long);
int main()
{
     long long num;
     cout << "Insert any binary number to be converted: ";
     cin >> num;
     cout << num << " is " << BinaryToDecimal(num) << " in Decimal";
     return 0;
}
int BinaryToDecimal(long long num)
{
    int ans = 0, x = 0, Rem;
    while (num!=0)
    {
        Rem = num%10;
        num /= 10;
        ans += Rem*pow(2,x);
        ++x;
    }
    return ans;
}

Insert any binary number to be converted: 101101100
101101100 is 364 in Decimal

• This function also uses recursion.
• A number is taken from the user num.
• Through recursion, num is divided by 10 and the remainder is stored in a variable Rem.
• To find the ans, ans = ans + Rem*pow(2,x). Remainder is multiplied by 2 powered x, and added to ans.
• The value of x is incremented by 1 through every iteration.