Determining Blank Spaces, Digits, Consonants, and Vowels In a String in C++

#include <iostream>
using namespace std;
int main()
{
    char words[100];
    int cons=0, vow=0, dig=0, spc=0;
    cout << "Insert any sentence: ";
    cin.getline(words, 100);
    for(int i = 0; words[i]!='\0'; ++i)
    {
        if(words[i]=='a' || words[i]=='e' || words[i]=='i' || words[i]=='o' || words[i]=='u'
        || words[i]=='A' ||words[i]=='E' || words[i]=='I' || words[i]=='O' ||words[i]=='U')
        {
            ++vow;
        }
        else if (words[i]==' ')
        {
            ++spc;
        }
         else if((words[i]>='a'&& words[i]<='z') || (words[i]>='A'&& words[i]<='Z'))
        {
            ++cons;
        }
        else if(words[i]>='0' && words[i]<='9')
        {
            ++dig;
        }
    }
    cout << "\nvowels: " << vow << endl;
    cout << "consonants: " << cons << endl;
    cout << "blank space: " << spc << endl;
    cout << "digits: " << dig << endl;
    return 0;
}

Insert any sentence: the answer to everything is 42
vowels: 8
consonants: 15
blank space: 5
digits: 2

• This code works similar to the frequency check code. The user is requested to enter a sentence.
• 1 by 1, each element of the string is assessed.
• If... else statements are used to check if the entered character is a vowel, capital or small.
• Else, it could be a consonant, digit, or a space.
• If present, vow, cons, dig, spc is incremented by 1 and then displayed on the screen.

#include <iostream>
using namespace std;
int main()
{
    string words;
    int cons=0, vow=0, dig=0, spc=0;
    cout << "Insert any sentence: ";
    getline(cin , words);         // string object
    for(int i = 0; words[i]!='\0'; ++i)
    {
        if(words[i]=='a' || words[i]=='e' || words[i]=='i' || words[i]=='o' || words[i]=='u'
        || words[i]=='A' ||words[i]=='E' || words[i]=='I' || words[i]=='O' ||words[i]=='U')
        {
            ++vow;
        }
        else if (words[i]==' ')
        {
            ++spc;
        }
        else if((words[i]>='a'&& words[i]<='z') || (words[i]>='A'&& words[i]<='Z'))
        {
            ++cons;
        }
        else if(words[i]>='0' && words[i]<='9')
        {
            ++dig;
        }
    }
    cout << "\nvowels: " << vow << endl;
    cout << "consonants: " << cons << endl;
    cout << "blank space: " << spc << endl;
    cout << "digits: " << dig << endl;
    return 0;
}

Insert any sentence: the answer to everything is 42
vowels: 8
consonants: 15
blank space: 5
digits: 2

• This code is similar to the code above.
• The only difference is that this code takes a string object from the user. The previous code accepts a C Style String.