Determining Character Frequency In a String In C++

#include <iostream>
using namespace std;
int main()
{
    string str;
    int check = 0;
    char find = 'o';    // to find any letter from a-z or A-Z
    cout<<"Enter a sentence to check o "<<endl;
    getline (cin,str);
    for (int x = 0; x < str.size(); x++)
    {
        if (str[x] ==  find)
        {
            ++ check;
        }
    }
    cout << "Number of " << find << " = " << check;
    return 0;
}

Enter a sentence to check o
code of code
Number of o = 3

• This code is used to count the number of repeatedly appearing characters in a string. To begin, the length of a character is stored using the for loop.
• Through every iteration where the character being checked for is present, the value of check is increased by 1.
• The iterations continue until the character is found empty (null).
• Through every iteration, it is checked if the character is present.

#include <iostream>
using namespace std;
int main ( )
{
    char c[] = "I learn programming from codeofcode.", check = 'r' ;
    int num = 0;
    for(int n=0; c[n] != '\0'; ++n)
{
    if (check == c[n])
    ++num;
}
cout << "The frequency of " << check << " in the sentence is: " <<num;
return 0;
}

The frequency of r in the sentence is: 4

• The code is similar to the above one.
• The loops continue until a null character '\0' is encountered which marks the ending of a sentence.
• The presence of the character is checked after each iteration.