Saving Student Information In a Structure In C++

#include <iostream>
using namespace std;
struct stdinfo
{
    char name[50];
    float marks;
    int rollno;
};
int main() 
{
    stdinfo i;
    cout << "Student's information" << endl;
    cout << "\nInsert name: ";
    cin >> i.name;
    cout << "Insert roll number: ";
    cin >> i.rollno;
    cout << "Insert marks: ";
    cin >> i.marks;
    cout << "\nDisplaying Information:" << endl;
    cout << "Name: " << i.name << endl;
    cout << "Roll no: " << i.rollno << endl;
    cout << "Marks: " << i.marks << endl;
    return 0;
}

Student's information

Insert name: john
Insert roll number: 1234
Insert marks: 89

Displaying Information:
Name: john
Roll no: 1234
Marks: 89

• 3 variables are initialized. The char type variable name [50]. This string can contain up to 50 elements for the name. A float type variable marks is used to store student’s score and an int type variable rollno for roll number.
• A structure is stdinfo is created and a variable for the structure i is created.
• The student is asked to enter the name, roll number, and marks and they’re stored in i, structure variable.
• The student data is printed onto the screen.